What will have to happen to the temperature of a sample of methane if 1000 mL at 98.6 kPa and 25°c is given a pressure of 108.5 kPa and a volume of 900 mL?

The temperature of the methane gas will drop to 22.127 °C.

Explanation:

To solve the question, we note tht the combined gas equation is given by

Where:

P₁ = Initial pressure = 98.6 kPa

V₁ = Initial volume = 1000 mL

T₁ = Initial temperature = 25°c = 298.15 K

P₂ = Final pressure = 108.5 kPa

V₂ = Final volume = 900 mL

T₂ = Final temperature = Required

Therefore we have

= =  295.277 K

The temperature T₂ < T₁

Therefore what will happen is that the temperature of the methane gas will drop by 2.873 °C from 25 °C to 22.127 °C.

answer: a chemical reaction

explanation:

im not wrong