The enthalpy of neutralization for the reaction of a strong acid with a strong base is -56 kJ/mol of water produced. How much energy will be released when 155.0 mL of 0.400 M HCl is mixed with 157.0 mL of 0.500 M NaOH?

 3.48 kJ of heat is released when 155.0 mL of 0.400 M HCl is mixed with 157.0 mL of 0.500 M NaOH

Explanation:

To calculate the number of moles for given molarity, we use the equation:

    .....(1)

Molarity of solution = 0.400 M

Volume of solution = 155.5 mL

Putting values in equation 1, we get:

a)

b)

According to stoichiometry;

1 mole of reacts with 1 mole of

Thus 0.0622 moles of reacts with= moles of

Thus HCl is the limitibg reagent and NaOH is in excess

1 mole of HCl gives = 56 kJ

Thus 0.0622 moles of HCl gives =

Thus 3.48 kJ of heat is released when 155.0 mL of 0.400 M HCl is mixed with 157.0 mL of 0.500 M NaOH

43.452

step-by-step explanation:

284 times .153 = 43.452