A sample of an ideal gas at 1.00 atm and a volume of 1.89 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 10.0 atm , what was the volume of the sample

The new volume is 0.189 L or 189 mL

Explanation:

Step 1: data given

Pressure of the gas = 1.00 atm

The volume of the gas = 1.89 L

The pressure increased to 10.0 atm

Step 2: Calculate the new volume

P1*V1 = P2*V2

⇒With P1 = the initial pressure = 1.00 atm

⇒with V1 = the initial volume = 1.89 L

⇒with P2 = the increased pressure = 10.0 atm

⇒with V2 = the new volume = TO BE DETERMINED

1.00 atm * 1.89 L = 10.0 atm * V2

V2 = 1.89 / 10.0

V2 = 0.189 L = 189 mL

The new volume is 0.189 L or 189 mL

43.452

step-by-step explanation:

284 times .153 = 43.452

it would be d. henry moseley

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