A 22.8-gram sample of gas is found to have a volume of 1.5 liters at 287 K and 0.98
atm. What is the molar mass of this gas? Show all of the work used to solve this
problem.

365.4 g/mol is the molar mass of this gas.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = 0.98 atm

V = Volume of gas = 1.5 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 287  K

Putting values in above equation, we get:

Moles of gas = n = 0.06239 mol

Mass of gas = m = 22.8 g

Molar mass of gas = M

365.4 g/mol is the molar mass of this gas.