What is the Complete Ionic Equation of Iorn(III) Chloride and Sodium Hydroxide?

The equation is based on Iron (III) not lorn(III)

Explanation:

FeCl₃(aq) + 3 NaOH(aq) ---> + 3 NaCl(aq)

[ Balanced Molecular Equation ]

+ 3 + 3 + 3 ---> + 3 + 3

[ Balanced Full Ionic Equation ]

+ 3 ---> Fe(OH)3(s)

[ Balanced Net Ionic Equation ]

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

the answer is:  

line graphs show patterns in data with variables that change over time; whereas, circle graphs show data as parts out of a whole (such as out of 100%).