Suppose of barium acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate anion in the solution. You can assume the volume of the solution doesn't change when the barium acetate is dissolved in it. Be sure your answer has the correct number of significant digits.

The question is incomplete, here is the complete question:

Suppose 2.19 g of barium acetate is dissolved in 150. mL of a 0.10 M aqueous solution of sodium chromate. Calculate the final molarity of acetate anion in the solution. You can assume the volume of the solution doesn't change when the barium acetate is dissolved in it. Be sure your answer has the correct number of significant digits.

The final molarity of acetate ions in the solution is 0.115 M

Explanation:

To calculate the number of moles, we use the equation:

Given mass of barium acetate = 2.19 g

Molar mass of barium acetate = 255.43 g/mol

Putting values in above equation, we get:

To calculate the number of moles for given molarity, we use the equation:

   .....(1)

Molarity of sodium chromate solution = 0.10 M

Volume of solution = 150 mL = 0.150 L     (Conversion factor:  1 L = 1000 mL)

Putting values in equation 1, we get:

The chemical equation for the reaction of barium acetate and sodium chromate follows:

By Stoichiometry of the reaction:

1 moles of barium acetate reacts with 1 mole of sodium chromate

So, 0.0086 moles of barium acetate will react with = of sodium chromate

As, given amount of sodium chromate is more than the required amount. So, it is considered as an excess reagent.

Thus, barium acetate is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 moles of barium acetate produces 2 moles of sodium acetate

So, 0.0086 moles of barium acetate will produce = of sodium acetate

1 mole of sodium acetate produces 1 mole of sodium ions and 1 mole of acetate ions

Now, calculating the molarity of acetate ions by using equation 1:

Moles of acetate ions = 0.0172 moles

Volume of solution = 0.150 L

Putting values in equation 1, we get:

Hence, the final molarity of acetate ions in the solution is 0.115 M

a is the answer to this question

explanation:

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.