Cerium (IV) ions are strong oxidizing agents in acid ic solution, oxidizing arsenio us acid to arsen ic acid accor ding to the following equa tion:
2Ce4+(aq)+H3AsO3(aq)+3H2O(l)→2Ce3+( aq)+H3AsO4(aq)+2H+(aq)
A sample of As2O3 weighing 0.217 g is dissolved in basic solution and then acidified to make H3AsO3. Its titration with a solution of acidic cerium{IV) sulfate requires 21.47 ml. Determine the original concentration of Ce^4+(aq) in the titrating solution

0.2042 M is the original concentration of (aq) in the titrating solution.

Explanation:

Mass of = 0.217 g

Moles of

1 mole of have 2 mole of As  and 1 mole of have 1 mole of As.

So, from 1 mole of we will have 2 moles of

Then from 0.001096 mol of :

of

According to reaction, 1 mole of reacts with 2 mole of cerium (IV) ions,then 0.002192 mol of

of cerium (IV) ions.

Volume of the  acidic cerium{IV) sulfate = 21.47 ml =0.02147 L

1 mL = 0.001 L

0.2042 M is the original concentration of (aq) in the titrating solution.

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa