Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq) , as described by the chemical equation

MnO2(s)+4HCl(aq)⟶MnCl2(aq)+2H2O(l)+ Cl2(g)

How much MnO2(s) should be added to excess HCl(aq) to obtain 385 mL Cl2(g) at 25 °C and 765 Torr ? mass of MnO 2

Explanation:

Hello,

In this case, we first apply the ideal gas equation to compute the moles of produced chlorine:

Then, by considering the given reaction, applying the stoichiometry, that shows a 1 to 1 relationship between chlorine and manganese dioxide, we find:

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hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b