For the Reaction represented by the equation below what mass of product will form if 34.6 moles of sodium react with excess chlorine gas

2024.1g

Explanation:

Given parameters:

Number of moles of Na  = 34.6moles

Unknown:

Mass of product formed  = ?

Solution:

We must first establish the reaction equation as shown below;

                2Na      +         Cl₂    →    2NaCl

We solve from the known to the unknown specie;

               2 moles of Na produced 2 moles of NaCl

           34.6moles of Na will produce 34.6moles of NaCl

Now to find the mass of NaCl;

     mass = number of moles x molar mass  = 34.6 x (23 + 35.5)  = 2024.1g