If 0.500 mole of calcium carbonate is produced in a particular reaction, how many moles of sodium chloride are produced in the same reaction?

CaCl2 (aq) + Na2CO3 (aq) → CaCO3 (s) + 2 NaCl (aq)

In the same reaction, 1.00 moles of NaCl are produced

Explanation:

Step 1: Data given

Number of moles calcium carbonate = 0.500 moles

Step 2: The balanced equation

CaCl2 (aq) + Na2CO3 (aq) → CaCO3 (s) + 2 NaCl (aq)

Step 3: Calculate moles sodium chloride (NaCl)

For 1 mol CaCl2 we need 1 mol Na2CO3 to produce 1 mol CaCO3 and 2 moles NaCl

For 0.500 moles CaCO3 produced we we'll have 2* 0.500 = 1.00 mol of NaCl produced

In the same reaction, 1.00 moles of NaCl are produced

i have no clue hope you find the answer

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.