Iron(III) sulfide reacts with hydrochloric acid to produce hydrogen sulfide and iron(II) chloride. Wright the formula equation for this reaction and balance it.

Fe2S3 + 4HCl —> 2H2S + 2FeCl2 + S

Explanation:

From the question, we were told that:

Iron(III) sulfide reacts with hydrochloric acid to produce hydrogen sulfide and iron(II) chloride.

Please note that elemental sulphur is produced along with this reaction. The equation for the reaction is given below:

Fe2S3 + HCl —> H2S + FeCl2 + S

Now, we can balance the equation as shown below:

There are 3 atoms of S on the left side of the equation and 2 atoms on the right. It can be balance by putting 2 in front of H2S as shown below:

Fe2S3 + HCl —> 2H2S + FeCl2 + S

Now, we have 4 atoms of H on the right side and 1atom on the left side. It can be balance by putting 4 in front of HCl as shown below:

Fe2S3 + 4HCl —> 2H2S + FeCl2 + S

Also, there are 4 atoms of Cl on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of FeCl2 as shown below:

Fe2S3 + 4HCl —> 2H2S + 2FeCl2 + S

Now, we can see that the equation is balanced

- aluminum and copper chloride.

- the chloride ion to separate the aluminum from the oxygen so that the aluminum can react with the copper ions (and the water molecules).

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