A graduate student is working in his lab. In order to continue his experiment, he needs to calculate the total number of ions in 9.24 mol of CaBr 2 . Calculate the total number of ions in the sample.

We have 9.24  moles Calcium ions and 18.48 moles bromide ions

Explanation:

Step 1: Data given

Number of moles CaBr2 = 9.24 moles

Step 2: The equation

CaBr2 →Ca^2+ + 2Br-

Step 3: Calculate number of moles

For 1 mol CaBr2 we have 1 mol Calcium ions and 2 moles Bromide ions

For 9.24 moles we have 1* 9.24 = 9.24  moles Calcium ions

For 9.24 moles we have 2-9.24 = 18.48 moles bromide ions

For 9.24 moles Ca^2+ we have 9.24 *6.022*10^23 =5.56*10^24 Calcium ions

For 18.48 moles Br- we have 1.1 * 10^25 bromide ions

1.67×10²⁵ ions in 9.24 moles of CaBr₂

Explanation:

First of all, we need to dissociate our compound:

CaBr₂ →  Ca²⁺  +  2Br⁻

This equation means, that 1 mol of calcium bromide dissociates in 3 moles of ions (1 mol of Ca²⁺ and 2 moles of bromide, Br⁻)

Let's make a rule of three:

In 1 mol of bromide we have 3 moles of ions

Then, in 9.24 moles of bromide we must have (9.24 . 3) /1 = 27.72 moles

Let's count the ions: 27.72 mol . 6.02×10²³ ions / 1mol = 1.67×10²⁵ ions

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

m=9

step-by-step explanation: