How much water, in grams, can be made from 1.03 x hydrogen molecules? Answer in units of g.

30.8 g of water are produced

Explanation:

First of all we need the equation for the production of water:

2H₂ + O₂ → 2H₂O

2 moles of hydrogen react with 1 mol of oxygen in order to produce 2 moles of water.

As we assume, the oxygen in excess, we determine the moles of H₂.

1.03ₓ10²⁴ molecules . 1 mol/ 6.02ₓ10²³ molecules = 1.71 moles

Ratio is 2:2, so 1.71 moles will produce 1.71 moles of water

Let's convert the moles to mass: 1.71 mol . 18g / 1mol = 30.8 g of water are produced

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

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