A sample of xenon gas at a pressure of 817 mm Hg and a temperature of 66 °C, occupies a volume of 13.9 liters. If the gas is heated at constant pressure to a temperature of 89 °C, the volume of the gas sample will be 14.84 L.

The value of heat transfer in xenon gas during heating at constant pressure  Q = 0.254  KJ

Explanation:

Initial pressure = 109 k pa = Final pressure

Initial temperature = 66°c = 339 K

Initial volume = 13.9 liter = 0.0139

Final temperature = 362 K

Final volume = 14.84 liter

Specific heat for xenon at constant pressure = 0.158

Gas constant  for xenon (R)= 0.063

From ideal gas equation

= m R ------ (1)

⇒ 109 × 0.0139 = m × 0.06333 × 339

⇒ m = 0.07 kg

This is the mass of xenon gas.

heat transfer is given by

Put all the value sin above equation we get

Q = 0.07 × 0.158 × (362 - 339)

Q = 0.254  KJ

This is the value of heat transfer in xenon gas during heating at constant pressure.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g