If the reaction of phosphate ion with water is ignored, what is the total concentration of ions in a solution prepared by dissolving 7.00 g of K3PO4 in enough water to make 350. mL of solution?

0.377 M

Explanation:

Given that:

mass of = 7.00 g

the molar mass of  = 212.27 g/mol

number of moles =

number of moles of =

= 0.0330

The dissociation of K₃PO₄(aq) → 3K⁺(aq) + PO₄³⁻(aq)

So number of Ions formed = 3 K + and 1 PO₄³⁻ = 4 ions

No of moles of ions = 4 × 0.0330

Molarity = 4 × 0.0330/ ( 350/1000)  

= 0.377 M

Hence, the   total concentration of ions in a solution prepared by dissolving  7.00 g of K3PO4 in enough water to make 350. mL of solution = 0.377 M

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :