Explain why a solution that is 1.3 M HF and 1.3 mM KF is not a good buffer. HF is a strong acid and cannot be used in a buffer system. The ratio of acid to conjugate base is outside the buffer range of 10:1. The two species are not a conjugate acid base pair. KF is not soluble in water and cannot be used in a buffer system.

The solution is not a good buffer as the ratio of acid to the conjugate base is outside the buffer range of 10:1. Thus statement B is correct.

The ratio of acid to the conjugate base can be calculated as:

pH = + log

For a solution that is 1.3 in HF and 1.3 in KF, the ratio is:

The ratio of acid to the conjugate base has been equal to 1:1000.

The ratio of acid to the conjugate base is outside the buffer range of 10:1. Thus the solution is not a good buffer. Thus statement B is correct.

For more information about the buffer system, refer to the link:

link

The ratio of acid to conjugate base is outside the buffer range of 10:1.

Explanation:

The Henderson-Hasselbalch equation for a buffer is

A buffer should have

For a solution that is 1.3 mol·L⁻¹ in HF and 1.3 mmol·L⁻¹ in KF, the ratio is

The ratio of acid to conjugate base is 1000:1, which is outside the range of 10:1.

A is wrong. NF is a weak acid.

C is wrong. The two species are a conjugate acid-base pair.

D is wrong. Salts of Group 1 metals are soluble.

i just learnt this recently but i need to look through my notes again