Answers: 2
.![pH=-\log[H^+]](/tpl/images/0554/0412/cf945.png)
![2.46=-\log[H^+]](/tpl/images/0554/0412/98673.png)
![[H^+]=0.003467 M](/tpl/images/0554/0412/5a2c6.png)
![K_a=\frac{[A^-][H^+]}{[HA]}](/tpl/images/0554/0412/a5cb9.png)
![x=[H^+]=0.003467 M](/tpl/images/0554/0412/5abc8.png)
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