How many milliliters of a 2.00 M KBr are needed to prepare 250.0 mL of 0.60 M KBr?

75mL

Explanation:

Data obtained from the question include:

C1 = 2M

V1 =?

C2 = 0.60M

V2 = 250mL

The original volume of solution can be obtained as follows:

C1V1 = C2V2

2 x V1 = 0.6 x 250

Divide both side by 2

V1 = (0.6 x 250) / 2

V1 = 75mL

The volume needed is 75mL

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .

its first and third is your answer i did the qustion the fourth isnt right