How many moles of each reactant are needed to produce 6.16 moles of HF?

Enter your answers numerically separated by a comma.

3.08 moles of CaF₂ and 3.08 mol of H₂SO₄

Explanation:

In order to produce HF we can assume this chemical reaction:

CaF₂ + H₂SO₄  → CaSO₄ + 2HF

1 mol of calcium fluoride can react to 1 mol of sulfuric acid in order to produce 1 mol of calcium sulfate and 2 moles of HF

In this case, ratio is 2:1 with both reactants. Let's make a rule of three:

2 moles of HF were produced by 1 mol of CaF₂ and 1 mol of H₂SO₄

Then, 6.16 moles of HF must be produced by:

(6.16 . 1) / 2 = 3.08 moles of CaF₂ and 3.08 mol of H₂SO₄

it is stable as it is in group 0 which have full outer shells of electrons