Calculate the mass of Cu deposited by the electrolysis of CuCl2 at 4A for 40 minutes.

3.16g

Explanation:

Data obtained from the question include:

I = 4A

t = 40mins = 40 x 60 = 2400secs

Q =?

Q = It

Q = 4 x 2400

Q = 9600C

Now let us generate a balanced half equation to determine the number faraday needed to deposit metallic Cu. This is illustrated:

Cu^2+ + 2e —> Cu

From the equation,

2 faraday is needed to deposit metallic cu

1 faraday = 96500C

Therefore 2 faraday = 2 x 96500 = 193000C

Molar Mass of Cu = 63.5g/mol

193000C deposited 63.5g of Cu

Therefore, 9600C will deposit = (9600 x 63.5)/193000 = 3.16g of Cu

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