A student is preparing to perform a series of calorimetry experiments. She first wishes to determine the calorimeter constant (Ccal) for her coffee cup calorimeter. She pours a 50.0 mL sample of water at 345 K into the calorimeter containing a 50.0 mL sample of water at 298 K. She carefully records the final temperature of the water as 317 K. What is the value of Ccal for the calorimeter

Explanation:

The given data is as follows.

      = 50 ml,       = 345 K

      = 298 K,       = 317 K,

    = 50 ml

Now, we will calculate the heat energy as follows.

                     =

                     = 5857.6 J

                     =

                     = 3974.8 J

As,   so there will be loss of heat. And, some heat will go to the calorimeter.

Hence,    

                = 1882.8 J

We assume that the temperature of (calorimeter + water) is 298 K. Hence,

                  dT =

                        = (317 - 298) K

                        = 19 K

Hence, we will calculate the specific heat as follows.

               C =

                   =

                   = 99.1 J/K

Thus, we can conclude that the value of for the calorimeter is 99.1 J/K.

i don,t know so just answer mine

0.88m hope i am correct : )