The decomposition of nitramide, O 2 NNH 2 , in water has the given chemical equation and rate law. O 2 NNH 2 ( aq ) ⟶ N 2 O ( g ) + H 2 O ( l ) rate = k [ O 2 NNH 2 ] [ H + ] A proposed mechanism for this reaction is:. ( 1 ) O 2 NNH 2 ( aq ) k 1 ⇌ k − 1 O 2 NNH − ( aq ) + H + ( aq ) (fast equilibrium) ( 2 ) O 2 NNH − ( aq ) k 2 −→ N 2 O ( g ) + OH − ( aq ) (slow) ( 3 ) H + ( aq ) + OH − ( aq ) k 3 −→ H 2 O ( l ) (fast)

answer; the enthalpy of both the return air and the outside air. ;

do u have any choices to choose from ? ?

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

bcde is the incorrect answer it is a