A bottle of commercial vinegar contains 5% acetic acid, ch3cooh, by volume (95% water). the density of acetic acid is 1.05 g/ml and water is 1.00 g/ml. from this data calculate the concentration of acetic acid in vinegar in: molality, molarity, parts by mass, and the mole fraction.

See explanation.

Explanation:

Hello,

For this exercise, it is convenient to assume a basis of 5 g of acetic acid which is the solute and 95 g of water which is the solvent, in such a way, one proceeds as follows:

(a) Molarity:

Thus:

(b) Molality:

In this case, the moles were already computed and the mass of the solvent is in kilograms, thus:

(c) Parts by mass:

(d) Mole fraction:

In this case, the moles of water are required:

Since:

Best regards.

if two electrons have the same n, the same ℓ, and the same ml, then they are in the same orbital. the pauli exclusion principle states that no two identical fermions (a fancy word for electrons and other subatomic particles like electrons) may occupy the same quantum state in an atom simultaneously.