For the following reaction, 5.61 grams of carbon monoxide are mixed with excess water . Assume that the percent yield of carbon dioxide is 85.3 %. carbon monoxide(g) water(l) carbon dioxide(g) hydrogen(g) What is the ideal yield of carbon dioxide

The ideal yield of carbon dioxide is 7.506 grams

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of carbon monoxide = 5.61 g

Molar mass of carbon monoxide = 28 g/mol

Putting values in equation 1, we get:

The chemical equation for the reaction of carbon monoxide and water follows:

By Stoichiometry of the reaction:

1 mole of carbon monoxide produces 1 mole of carbon dioxide

So, 0.200 moles of carbon monoxide will produce = of carbon dioxide

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 0.200 moles

Putting values in equation 1, we get:

To calculate the experimental yield of carbon dioxide, we use the equation:

Percentage yield of carbon dioxide = 85.3 %

Theoretical yield of carbon dioxide = 8.8 g

Putting values in above equation, we get:

Hence, the ideal yield of carbon dioxide is 7.506 grams

im not exactly sure but i think its b!

that's what i got you can count the number of atoms