Which one of the following equations is the net ionic equation for the reaction of aqueous sodium hydroxide (NaOH) with aqueous hydrochloric acid (HCl)? HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l) H+(aq) + Cl‒(aq) + Na+(aq) + OH‒(aq) → Na+(aq) + Cl‒(aq) + H2O(l) H+(aq) + Cl‒(aq) + Na+(aq) + OH‒(aq) → NaCl(aq) + H2O(l) H+(aq) + OH‒(aq) → H2O(l)

H+(aq) +  OH-(aq) → H2O(l)

Explanation:

Step 1: Data given

aqueous sodium hydroxide = NaOH(aq)

aqueous hydrochloric acid =HCl(aq)

Step 2: The (un)balanced equation

HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)

For 1 mol HCl we need 1 mol NaOH to produce 1 mol NaCl and 1 mol H2O

This equation is already balanced.

Step 3: The net ionic equation

H+(aq) + Cl-(aq) + Na+(aq) + OH-(aq) → Na+(aq) + Cl-(aq) + H2O(l)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side, look like this:

H+(aq) +  OH-(aq) → H2O(l) (The last option is correct)

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.