Calculate the volume, in liters and to the hundredths place, of a stock solution that has a concentration of 0.235 M Ca(NO3)2 and when diluted to a 0.872 L becomes 0.18 M Ca(NO3)2.

0.670L is the volume for the concentrated solution

Explanation:

There is an element that indicates the relation between Molarity of concentrated solution with Molarity of diluted solution or their volumes.

This is the dilution factor.

We can apply like this:

Molarity of concentrated / Molarity of diluted = Volume of diluted / Vol. conc.

We replace data: 0.235 M / 0.18 M = 0.872L / Volume of concentrated

1.30 = 0.872L / Volume of concentrated

Volume of concentrated = 0.872L / 1.30

Volume of concentrated = 0.670L

The volume of the stock solution = 0.053L

Explanation:

Step 1: Data given

Concentration of the stock solution = 0.235 M Ca(NO3)2

Concentration of the diluted solution =0.18 M Ca(NO3)2

Volume of the diluted solution = 0.872 L

Step 2: Calculate the volume of the stock solution

C1*V1 = C2*V2

⇒with C1 = the concentration of the stock solution = 0.235 M Ca(NO3)2

⇒with V1 = the volume of the stock solution = TO DETERMINED

⇒with C2 = the concentration of the diluted solution = 0.18 M Ca(NO3)2

⇒with V2 = the volume of the diluted solution = 0.872 L

1.5 M * V1 = 0.80 M * 0.10 L

V1 = 0.053 L

0.053 L of stock solution was used.

the answer is b & c i believe : )

the answers would be

the first one and the second one