Calculate the concentration of NaCl in a solution prepared by diluting 2 mL of 0.05 M NaCl to a total volume of 10 mL with deionized water. What is the total concentration of ions in the diluted solution

0.02M  is the total concentration of ions in the diluted solution

Explanation:

We can apply the formula for dilution, to determine the [NaCl]

2 mL . 0.05M = 10 mL . M

M = 2 mL . 0.05M / 10 mL → 0.01 M

In order to determine the [ions] we dissociate our solute:

NaCl → Na⁺ + Cl⁻

Our solute concentration in diluted solution is 0.01M and the ratio with the ions is 1:1, so the total concentration of ions in the diluted solution is:

[Na⁺] + [Cl⁻] = 0.01 + 0.01 = 0.02M

For x moles of NaCl, it corresponds x moles of Na cation and x moles of  Cl anion.

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answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error