Balance equation C5H10+O2=CO2+H2O

2 C5H10 + 15 O2 => 10 CO2 + 10 H2O

Explanation: Each individual atom both in the reactant and product side have equal number of atoms.

Reactant Product

Carbon 10 10

Hydrogen 20 20

Oxygen 30 30

2C5H10 + 15O2 —> 10CO2 + 10H2O

Explanation:

C5H10 + O2 —> CO2 + H2O

To balance the equation, do the following:

There are 5 atoms of C on the left side of the equation and 1atom on the right side. It can be balance by putting 5 in front of CO2 as shown below:

C5H10 + O2 —> 5CO2 + H2O

There are 10 atoms of H on the left side and 2 atoms on the right. It can be balance by putting 5 in front of H2O as shown below:

C5H10 + O2 —> 5CO2 + 5H2O

Now, there are a total of 15atoms of O2 on the right side and 2 atoms on the left side. It can be balance by putting 15/2 in front of O2 as shown below:

C5H10 + 15/2O2 —> 5CO2 + 5H2O

Now multiply through by 2 to clear the fraction as shown below:

2C5H10 + 15O2 —> 10CO2 + 10H2O

Now the equation is balanced

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).

they are all solids.