The rate constant for this second‑order reaction is 0.990 M − 1 ⋅ s − 1 0.990 M−1⋅s−1 at 300 ∘ C. 300 ∘C. A ⟶ products A⟶products How long, in seconds, would it take for the concentration of A A to decrease from 0.650 M 0.650 M to 0.380 M?

Answer : The time taken would be, 1.10 s

Explanation :

The integrated rate law equation for second order reaction follows:

where,

k = rate constant =

t = time taken  = ?

[A] = concentration of substance after time 't' = 0.380 M

= Initial concentration = 0.650 M

Now put all the given values in above equation, we get:

Hence, the time taken would be, 1.10 s

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

so she was walking and she stepped on warm jeffy , uh uh uhh dadye i just pooped my pants