Calculate the homogeneous nucleation rate in liquid copper at undercoolings of 150, 175, and 200 K using the following data: L = 1.88 x 109 J/m⁻³ , Tm = 1356 K, γ_SL = 0.177 J/m⁻², f0 = 10¹¹ /s⁻¹, Co = 6 x 10²⁸ atoms/m³, k = 1.38 x 10⁻²³ J/K. Equation: N_hom = f0.Co. exp {(-16 π γSL³ Tm²/ 3 Lo² K T). (1/ΔT²)}

precipitation

explanation:

when it goes from cloud to rain/back to earth in the form of rain

yes

ya te ayud espera

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2