A sample of SO2 gas has a volume of 5.2 L. It is heated at constant pressure from 30.o oC to 90.0°C. What is its new volume? (Hint: Which law will you apply of the pressure is constant

Its new volume 6.22 L

Explanation:

Given,

Initial volume (V₁) = 5.2 L

Initial temperature(T₁) = 30℃ = 30+273 = 303K

Final temperature (T₂) = 90℃ = 90+ 273 = 363K

Final volume (V₂) = ?

According to Charles law : At constant pressure,volume of gas is directly proportional to the temperature .

That is, V ∝ T

V = KT ,where K = proportionality constant

V/T = constant

V₁ / T₁ = V₂ / T ₂

5.2 / 303 = V₂ / 363

V₂ = (5.2×363) / 303

V₂ = 6.22 L

The volume will e increased to a new volume of 6.23 L

Explanation:

Step 1: Data given

Volume of SO2 = 5.2 L

Initial temperature = 30.0 °C

Temperature is increased to 90.0 °C

Pressure will stay constant

Step 2: Calculate new volume

V1/T1 = V2/T2

⇒with V1 = the initial volume = 5.2 L

⇒with T1 = the initial temperature = 30.0 °C = 303 K

⇒with V2 = the final volume = TO BE DETERMINED

⇒with T2 = the new temperature = 363 K

5.2 L / 303 K = V2 / 363 K

V2 = 6.23 L

The volume will e increased to a new volume of 6.23 L

the right answer is c i just did the question.