Calculate the standard reaction free energy of the following chemical reaction:

2Al(s)+ Fe2O3(s) → Al2O3(s)+ 2Fe(s)

The question is incomplete, the complete question is:

Calculate the standard enthalpy change for a reaction? : Fe2O3(s) + 2Al(s) = Al2O3(s) + 2Fe(s).

The standard enthalpies of formation of Fe2O3 and Al2O3 are

-822 and -1669 KJ mol-1 respectively. State whether the reaction is exothermic or

endothermic

∆H°reaction= -847KJmol-1

Explanation:

Recall that ∆H°element =0KJ mol-1

Therefore

∆H°reaction = ∆H°products - ∆H°reactants

= (-1669)-(-822)= -847KJmol-1

The reaction is exothermic as ∆H°reaction is negative.

c. heat could easily travel through the molecules in the air and escape/enter the flask. removing the air slows down the heat transfer.  

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