A gaseous compound containing carbon and hydrogen was analyzed and found to consist of 83.65% carbon by mass. What is the empirical formula of the compound

Explanation:

The empirical formula of a compound represents the ratio of elements present in it but not the actual number of atoms.

Let the total mass of compound is 100 gram.

Then  mass of carbon would be is 83.65 gram .

Moles of carbon = 83.65/12 = approx 7 mole  (approx)

Mass of hydrogen present in the compound would be 100 - 83.65

                                                                                        = 16.35  gram

Moles of hydrogen = 16.35/1 = 16 mole (approx)

Therefore, the empirical formula of the compound would be

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied