The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) How many grams of O 2 ( g ) are needed to completely burn 89.2 g C 3 H 8 ( g ) ?

The mass of needed is, 13.59 grams.

Explanation : Given,

Mass of = 89.2 g

Molar mass of = 42 g/mol

Molar mass of = 32 g/mol

First we have to calculate the moles of

Now we have to calculate the moles of

The balanced chemical equation is:

From the reaction, we conclude that

As, 1 mole of react with 5 mole of

So, 2.124 mole of react with mole of

Now we have to calculate the mass of

Therefore, the mass of needed is, 13.59 grams.

50.23 i believe is correct but don't quote me on that.