A 5.00 mL sample of vinegar, an aqueous solution of acetic acid (HC2H3O2), is titrated with 0.0599 M Ca(OH)2, and 33.93 mL of the Ca(OH)2 solution is required to reach the equivalence point. What is the molarity of the acetic acid? Group of answer choices

Molarity of acetic acid is 0.812 M

Explanation:

Balanced reaction:

According to balanced equation, 1 mol of neutralizes 2 moles of

Number of moles of in 33.93 mL of 0.0599 M =

Let's assume molarity of is C (M)

Then, number of moles acetic acid were neutralized  =

So,

or,

So, molarity of acetic acid is 0.812 M      

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