The body metabolizes glucose (C6H12O6) by burning it with oxygen to produce carbon dioxide, water and energy. If 3 moles of glucose are burned, what volume of CO2 (g) is produced at STP

18g

Explanation:

1 mle of glucose combusts to give 6moles of CO2 and 6moles of H2O

C6H12O6 + 6O2 6CO2 + 6H2O at STP.

Multiplying 6 by 3 moles we have 18 g of CO2

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2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !