The chemical equation shows how ammonia reacts with sulfuric acid to produce ammonium sulfate. 2NH3(aq) + H2SO4(aq) (NH4)2SO4(aq) How many grams of ammonium sulfate can be produced if 60.0 mol of sulfuric acid react with an excess of ammonia

7923.6 g of (NH₄)₂SO₄ can be produced by this reaction

Explanation:

The reaction is:

2NH₃ (aq) + H₂SO₄(aq)  → (NH₄)₂SO₄(aq)

In this reaction ratio is 1:1.

As the ammonia is in excess, the limiting reagent is the sulfuric acid.

So 1 mol of sulfuric can produce 1 mol of sulfate

Then, 60 moles of sulfuric must produce 60 moles of sulfate.

We convert the moles to mass:

60 mol . 132.06 g / 1mol = 7923.6 g

i believe you are right for all except the 3rd ( look at sqdancefan his answer is much better)

i just learnt this recently but i need to look through my notes again