Write a balanced chemical equation for the reaction of aqueous sodium carbonate with aqueous barium chloride to form solid barium carbonate and aqueous sodium chloride.

Na₂CO₃(aq) + BaCl₂(aq) → BaCO₃(s) + 2NaCl(aq)

Explanation:

A double-replacement reaction is defined as a reaction where two compounds react, forming two new compounds or products. In the reaction of the problem:

Aqueous sodium carbonate -Na₂CO₃(aq)- and aqueous barium chloride -BaCl₂(aq)- produce solid barium carbonate -BaCO₃(s)- and aqueous sodium chloride -NaCl(aq)-. The reaction is:

Na₂CO₃(aq) + BaCl₂(aq) → BaCO₃(s) + 2NaCl(aq)

I hope it helps!

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years

your answers are a,b,,e and f

i hope this