Calculate the change in enthalpy associated with the combustion of 492.2 g of sulfur. Report your answer with four significant figures. Do not include a comma in your answer.

The question is incomplete, complete question is :

Calculate the change in enthalpy associated with the combustion of 492.2 g of sulfur. Report your answer with four significant figures. Do not include a comma in your answer.

-4,565 kJ the change in enthalpy associated with the combustion of 492.2 grams of sulfur.

Explanation:

Enthalpy change when 1 mole of sulfur is combusted = -296.8 kJ

Mass of sulfur = 492.2 g

Moles of sulfur =

Enthalpy change when 15.38 moles of sulfur:

-4,565 kJ the change in enthalpy associated with the combustion of 492.2 grams of sulfur.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.