At a certain temperature, 0.900 mol SO 3 is placed in a 2.00 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equilibrium, 0.110 mol O 2 is present. Calculate K c .

The value of is 0.0057

Explanation:

Initial moles of   = 0.900 mole

Volume of container = 2.00 L

Initial concentration of  

equilibrium concentration of [/tex]

The given balanced equilibrium reaction is,

Initial conc.              0.450 M               0        0

At eqm. conc.    (0.450 -2x) M         (2x) M   (x) M

The expression for equilibrium constant for this reaction will be,

we are given : x = 0.055

Now put all the given values in this expression, we get :

Thus the value of the equilibrium constant is 0.0057

they are both synthetic elements

explanation:

d