A container holds 500 mL of oxygen gas at a pressure of 1.3 atm and a temperature of 25 ˚C. If the temperature increases to 29 ˚C and the pressure increases to 2.0 atm, will the volume of the gas increase or decrease? What is the final volume of the gas in liters (L)?

The new volume of the gas is decreased, to 0.329 L

Explanation:

Step 1: Data given

Volume of oxygen = 500 mL = 0.500 L

Pressure = 1.3 atm

Temperature = 25.0 °C

Temperature increases to 29.0 °C

New pressure = 2.0 atm

Step 2: Calculate new volume

p1*V1/T1 = p2*V2/T2

⇒with p1 = the initial pressure = 1.3 atm

⇒with V1 = the initial volume = 0.500L

⇒with T1 = the initial temperature = 25 °C = 298 K

⇒with p2 = the new pressure = 2.0 atm

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the new temperature = 29 °C = 302 K

(1.3 * 0.500)/298 = (2.0 * V2) /302

0.0021812 = 2.0V2 / 302

V2 = 0.329 L = 329 mL

The new volume of the gas is decreased, to 0.329 L

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