Plz help me
Calculate the maximum mass of carbon dioxide that could be obtained by adding excess hydrochloric acid
to 15 g of calcium carbonate.
CaCO3 + 2HCI — CaCl2 + H2O + CO2

6.6 g

Explanation:

The mole ration between CaCO₃and CO₂ is 1 : 1

Because the molar mass of CaCO₃ is 100.0869 g/mol the amount of moles used in this chemical reaction is;

15/ 100

This will be similar to the moles of CO₂

Because the molar mass of CO₂ is 44g, then well multiply by the moles;

15/100 * 44

= 6.6 g

it is the most commonly accepted one

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3