A student prepares a solution by dissolving 60.00 g of glucose (molar mass 180.2 g mol-1) in enough distilled water to make 250.0 mL of solution. The molarity of the solution should be reported as
a. 12.01 M
b. 12.0 M
c. 1.332 M
d. 1.33 M
e. 1.3 M

1.332 Molar is the molarity of the glucose solution.

Explanation:

Molarity of the solution is the moles of compound in 1 Liter solutions.

Mass of glucose = 60.00 g

Molar mass of glucose = 180.2 g/mol

Volume of the solution = V = 250.0 mL = 0.250 L

(1 mL  = 0.001 L)

1.332 Molar is the molarity of the glucose solution.

the answer is definitely c.

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