If 75 g of metal at 100.0∘C is transferred into 80.0 mL of water at 20.0∘C initially. The water is then raised to 25∘C. What is the specific heat of the metal?

Answer : The specific heat of the metal is,

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

where,

= specific heat of metal = ?

= specific heat of water =

= mass of metal = 75 g

= mass of water  =

= final temperature of mixture =

= initial temperature of metal =

= initial temperature of water =

Now put all the given values in the above formula, we get

Therefore, the specific heat of the metal is,

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.