For the hypothetical reaction 2A B -> 2C D, the initial rate of disappearance of A is 1.6x10^-1 mol/(L s) . what is the initial rate of disappearance of B

0.8 x10^-1 mol/(L s)

Explanation:

2A + B -> 2C + D

For the reaction above, the differential rate is usually expressed as;

Rate = - (1 / 2) Δ[A] / Δt = - Δ[B] / Δt

The negative sign denotes disappearance.

Upon comparing ;  (1 / 2) Δ[A] / Δt = Δ[B] / Δt

If  initial rate of disappearance of A is 1.6x10^-1 mol/(L s);

That means

Δ[B] / Δt = 1.6x10^-1 mol/(L s) / 2

Δ[B] / Δt = 0.8 x10^-1 mol/(L s)

The initial rate of disappearance of B = 1.6x10^-1 mol/(L s)

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)