A 3.00 L sample of oxygen at a temperature of 250K has a pressure of 1.50atm. What will be the new pressure if the temperature is raised to 486K and the volume expands to 4.50 L

1.94 atm

Explanation:

(P1V1)/T1 = (P2V2)/T2

(3 * 1.5)/250 = (4.5 * P2)/486

Solve for P2 = 1.94 atm

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2