10.6 grams of Na2CO3 is dissolved in water to make 1.25 liters
of solution. What is the molarity of the solution? (Molar mass of
Na2CO3 = 106 g/mol) __M.

Molarity = 0.08 M

Explanation:

Given data:

Mass of sodium carbonate = 10.6 g

Volume of water = 1.25 L

Molarity of solution = ?

Solution:

First of all we will calculate the moles of solute.

Number of moles = mass/molar mass

Number of moles = 10.6 g/ 106 g/mol

Number of moles = 0.1 mol

Formula:

Molarity = moles of solute / volume of solution in L

Now we will put the values in formula.

Molarity = 0.1 mol / 1.25 L

Molarity = 0.08 M