How would the calculated ratio of water molecules present in Epsom salt be affected if the procedure was changed so the analysis was preformed using 2.500g of hydrated salt instead of 1.500g? Assume you still heated the sample to a constant mass. (Too High, Too Low, Unchanged) Explain

Unchanged

Explanation:

Epsom salt is also referred to as magnesium sulphate heptahydrate with the chemical formula

There are 7 moles of water and 1 mole of magnesium sulphate in every 1 mole of epsom salt. The water ratio remains the same irrespective of the amount or weight of epsom salt taken.

Hence, if 2.500 g of epsom salt is taken and heated to a constant mass instead of 1.500 g, the ratio of water molecules present will be the same.

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