When the concentrations of CH 3 Br and NaOH are both 0.100 M, the rate of the reaction is 0.0030 M/s. What is the rate of the reaction if the concentration of CH 3 Br is doubled?

Answer : The rate of the reaction if the concentration of is doubled is, 0.006 M/s

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The balanced equations will be:

In this reaction, and are the reactants.

The rate law expression for the reaction is:

As we are given that:

= concentration of = 0.100 M

= concentration of = 0.100 M

Rate = 0.0030 M/s

Now put all the given values in the above expression, we get:

Now we have to calculate the rate of the reaction if the concentration of is doubled.

Thus, the rate of the reaction if the concentration of is doubled is, 0.006 M/s

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."