A sample of helium (He) gas initially at 23°C and 1.0 atm is expanded from 1.3 L to 3.1 L and simultaneously heated to 44°C. Calculate the entropy change for the process.

Answer : The change in entropy is, 8.65 J/K

Explanation :

Formula used :

where,

= change in entropy

n = number of moles of gas  = 1 mole

R = gas constant  = 8.314 J/mol.K

= specific heat capacity at constant volume = (for monoatomic gas)

= initial volume of gas  = 1.3 L

= final volume of gas  = 3.1 L

= initial volume of gas  =

= final volume of gas  =

Now put all the given values in the above formula, we get:

Therefore, the change in entropy is, 8.65 J/K

false

because it does not have the potential to be entirely used up

3 1/4 %

explanation: